Question

If 2/5 of a number exceeds 1/7 of the same number by 36. Find the number.

Answer 1

The number x say

2x/5=1/7×x+36

2x/5=x/7+3

Transposing 7 to left side it become =×

2x -5x=36

Lcm 5,7 = 35

14x-5x / 35 = 36

9x/ 35 =36

Transposing 35 to right side it become =×

9x =36×35

X= 36×35/9 simplify with 9 table

4 ×35

= 140

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Answer 2

Given,

2/5 of a number exceeds 1/7 of the same number by 36

To Find,

The number =?

Solution,

We can solve the question as follows:

It is given to us that 2/5 of a number exceeds 1/7 of the same number by 36. Let the number be equal to x.

Now, 2/5 of x exceeds 1/7 of x by 36.

In equation form,

$\frac{2}{5} *x = \frac{1}{7} *x + 36$

$\frac{2x}{5} - \frac{x}{7} = 36$

Taking the LCM of 5 and 7, we get 35.

$\frac{14x - 5x}{35} = 36$

$\frac{9x}{35} = 36$

$9x = 36*35$

$x = \frac{36*35}{9}$

$x = 4*35 = 140$

Hence, the number is equal to 140.