if 2/5 of a number exceeds 1/7 of the same number by 36find the number
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Answered by
23
let number be x
2/5+×x=1/7×x +36
9/35×x=36
x=140
2/5+×x=1/7×x +36
9/35×x=36
x=140
rakeshsangwan10:
that's your answer
Answered by
41
Heya !!!
Let the number be X.
2/5 of X = 2/5 × X = 2X/5
And,
1/7 of X = 1/7 × X = X/7
According to question,
2/5 of a number = X/7 + 36
2X/5 = X/7 + 36
2X/5 = X + 252/7
7 ( 2X) = 5 ( X + 225)
14X = 5X + 1260
14X - 5X = 1260
9X = 1260
X = 1260/9 = 140.
Hence,
Number is 140.
★ HOPE IT WILL HELP YOU ★
Let the number be X.
2/5 of X = 2/5 × X = 2X/5
And,
1/7 of X = 1/7 × X = X/7
According to question,
2/5 of a number = X/7 + 36
2X/5 = X/7 + 36
2X/5 = X + 252/7
7 ( 2X) = 5 ( X + 225)
14X = 5X + 1260
14X - 5X = 1260
9X = 1260
X = 1260/9 = 140.
Hence,
Number is 140.
★ HOPE IT WILL HELP YOU ★
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