Question

if 2/5 of a number exeeds1/7 of the same number by 36.Find the number.​

Answer 1

Let the number be x
2/5 of the no. = (2x/5)
1/7 of the no. = (x/7)
It is given that 2x/5  exceeds  x/7  by  36
⇒ 2x/5  =  (x/7)+36
⇒ 2x/5  -  x/7  = 36
⇒ (14x - 5x)/35 = 36
⇒ 9x/35 = 36
⇒ 9x = 36×35
⇒ 9x = 1260
⇒ x = 1260/9
∴ x =140
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Answer 2

Let the number be x

According to question,

$\frac{2}{5} x = \frac{1}{7}x + 36 \\ \\ = > \frac{2}{5} x = \frac{x + (7 \times 36)}{7} \\ \\ = > 2x \times 7 = 5x + 5(7 \times 36) \\ \\ = > 14x = 5x + 35 \times 36 \\ \\ = > 14x - 5x = 35 \times 36 \\ \\ = > 9x = 35 \times 36 \\ \\ = > x = \frac{35 \times 36}{9} \\ \\ = > x = 35 \times 4 \\ \\ = > x = 140$

Therefore required number is 140