Question

If 2/5 th of a number exceeds 3/10 of another number by twice of 17 and 190 is the sum of that two numbers then the biggest of them is: A.120 B.130 C.165 D.132

Answer 1

Answer:

B:130

Step-by-step explanation:

let first number be x and 2nd be y

so according to the condition

(2/5)x=(3/10)y+2×17

x+y=190

now its easy