If 2/5 th of a number exceeds 3/10 of another number by twice of 17 and 190 is the sum of that two numbers then the biggest of them is: A.120 B.130 C.165 D.132
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Answer:
B:130
Step-by-step explanation:
let first number be x and 2nd be y
so according to the condition
(2/5)x=(3/10)y+2×17
x+y=190
now its easy
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