Question

If 2.500 g of NaHCO3 (MW = 84.007 g/mol) is reacted with 4.5 mL of HCI (Molarity = 12.0 mol/Liter, MW = 36.461 g/mol), please determine the theoretical yield of NaCl (MW 58.44 g/mol) in grams (g) produced.

NaHCO3 (s) + HCl (aq) NaCl (aq) + H2O (1) + CO2(g)​

Answer 1

Answer:

CALCULATIONS 4 pts 1. If 2.500 g of NaHCO3 (MW = 84.007 g/mol) is reacted with 4.5 mL of HCl (Molarity = 12.0 mol/Liter, MW = 36.461 g/mol), please determine the theoretical yield of NaCl (MW = 58.44 g/mol) in grams (g) produced. Please show all work for credit. NaHCO3 (3) + HCl (aq) → NaCl (aq) + H20 (1) + CO2 (g) 1. Moles of NaHCO3 2. Moles of HC1 3. Theoretical yield in Moles 4. Theoretical yield in grams

Explanation:

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