Question

If 2^5x\2^x=5✓32 find the value of x

Answer 1

$\frac{ {2}^{5x} }{ {2}^{x} } = \sqrt[5]{32} \\ \\ {2}^{5x - x} = \sqrt[5]{ {2}^{5} } \\ \\ {2}^{4x} = {2}^{1} \\ \\ 4x = 1 \\ \\ x = \frac{1}{4}$

Answer 2

Answer:

→ $\Huge \frac{1}{4}$

Step-by-step explanation:

$\begin{lgathered}\frac{ {2}^{5x} }{ {2}^{x} } = \sqrt[5]{32} \\ \\ {2}^{5x - x} = \sqrt[5]{ {2}^{5} } \\ \\ {2}^{4x} = {2}^{1} \\ \\ 4x = 1 \\ \\ x = \frac{1}{4}\end{lgathered}$