Question

. If (2, 6), (−1, −8), (−2, 6) and (1, −8) are the vertices of a quadrilateral, find its area​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The quadrilateral ABCD can be divided into triangles ABC and ACD and hence the area of the quadrilateral is the sum of the areas of the two triangles. 

Area of a triangle with vertices (x1,y1) ; (x2,y2)  and (x3,y3)  is ∣∣∣∣∣2x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣∣∣∣∣

Area of quadrilateral ABCD = area of triangle ABC + area of triangle ACD

area of △ABC=21[−3(−7+8)+(−2)(−8−5)+1(5+7)]

=21[35] sq. units

area of △ACD=21[−3(−8−3)+1(3−5)+6(5+8)]

=2