Question

if (2,6), (-1,-8), (-2,6) and (1,-8) are the vertices off the a quadrilateral find is area​

Answer 1

Answer:

ANSWER

Given, vertices of quadrilateral : A(−3,5),B(−2,−7),C(1,−8)andD(6,3)

Area of quadrilateral = Area of △ABC + Area of △DAC

Area of triangle =

2

1

(x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

))

Area of △ABC =

2

1

∣(−3(−7+8)−2(−8−5)+1(5+7))∣

=

2

1

∣(−3+26+12)∣

=

2

35

Area of △ADC =

2

1

∣(−3(3+8)+6(−8−5)+1(5−3))∣

=

2

1

∣(−33−78+2)∣

=

2

109

Area of quadrilateral =

2

35

+

2

109

Area of quadrilateral = 72cm

2