if 2√6-√5/3√5-2√6=x+ √30y, where x and y are rational numbers, find the value of x and y
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Step-by-step explanation:
We have,
2−32+3=x+y3
On rationalizing the denominator, we get:
2−32+3×2+32+3=x+y3
⇒22−(3)2(2+3)2=x+y3
⇒4−34+3+43=x+y3
⇒7+43=x+y3
On comparing both sides, we get:
x=7,y=4
Hence, the values of x and y are
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