If 2+6+7=24, 3+4+4=40 and 8+2+8=73 Then 7+3+9=??
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The sequence goes with this formula :
a+b+c=a*b*c-(2*(c-a)*b)+(c-a-1)*(c-b-1)*(2c-2b-1)
2+6+7=2*6*7-(2*(7-2)*6))+((7-2-1)*(7-6-1)(2*7-2*6-1)
= 84-60-0 = 24
3+4+4 = 3*4*4-(2*(4-3)*4)+(4-3-1)*(4-4-1)(2*4-2*4-1)
= 48-8 = 40
8+2+8 = 8*2*8-(2*(8-8)*2)+(8-8-1)*(8-2-1)(2*8-2*2-1)
128+0-55 = 73
7+3+9 = 7*3*9-(2*(9-7)*3)+(9-7-1)*(9-3-1)(2*9-2*3-1)
= 232
a+b+c = 232
So, Therefore 7+3+9 = 232
#BeBrainly
a+b+c=a*b*c-(2*(c-a)*b)+(c-a-1)*(c-b-1)*(2c-2b-1)
2+6+7=2*6*7-(2*(7-2)*6))+((7-2-1)*(7-6-1)(2*7-2*6-1)
= 84-60-0 = 24
3+4+4 = 3*4*4-(2*(4-3)*4)+(4-3-1)*(4-4-1)(2*4-2*4-1)
= 48-8 = 40
8+2+8 = 8*2*8-(2*(8-8)*2)+(8-8-1)*(8-2-1)(2*8-2*2-1)
128+0-55 = 73
7+3+9 = 7*3*9-(2*(9-7)*3)+(9-7-1)*(9-3-1)(2*9-2*3-1)
= 232
a+b+c = 232
So, Therefore 7+3+9 = 232
#BeBrainly
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