Question

if (2,6) if one of the extremities of a diameter of a circle with center (3,5) find the other end find the answer ​

Answer 1

Answer:Answer :

B(7,−8)

Solution :

Centre of the circle is C(3,−52)

.

One end of the diameter AB is A(−1,3)

Let the other end of the diameter be B(α,β).

Then, C is the midpoint of AB.

∴(−1+α2=3and3+β2=−52)⇒(α=7andβ=−8).

Step-by-step explanation: