Question

If (-2,6) is the image of the point
(4,2) w.r.t the line L = 0 then L = how much​

Answer 1

Answer:

(-2,6) is the image of the point (4,2) w.r.t. L=0. So, L=0 is the perpendicular bisector of (-2,6) , (4,2). Therefore, L=0 is (-2-4)x+(6-2)y = [(-2)2+62]-{42+22]/2.

Answer 2

(-2,6) is the image of the point (4,2) w.r.t. L=0. So, L=0 is the perpendicular bisector of (-2,6) , (4,2). Therefore, L=0 is (-2-4)x+(6-2)y = [(-2)2+62]-{42+22]/2.