if (-2, 6) is the image of the point (4,2) with respect
to line L = 0, then find the equation of line L.
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(-2,6) is the image of the point (4,2) w.r.t. L=0. So, L=0 is the perpendicular bisector of (-2,6) , (4,2). Therefore, L=0 is (-2-4)x+(6-2)y = [(-2)2+62]-{42+22]/2.
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