Question

If 2, –7 and –14 are the sum, sum of the product of its zeroes taken two at a time and the product of its zeroes of a cubic polynomial, then the cubic polynomial is

Answer 1

Answer:

${ x}^{3} - 2 {x}^{2} - 7x + 14$

Step-by-step explanation:

$f(x) = {x}^{3} - (\alpha + \beta + \gamma ) {x}^{2} +( \alpha \beta + \beta + \gamma \alpha )x - \alpha \beta \gamma$

$f(x) = {x}^{3} - 2 {x}^{2} - 7x + 14$

is the required answer

Answer 2

Step-by-step explanation:

Step-by-step explanation:

f(x) = {x}^{3} - (\alpha + \beta + \gamma ) {x}^{2} +( \alpha \beta + \beta + \gamma \alpha )x - \alpha \beta \gammaf(x)=x

3

−(α+β+γ)x

2

+(αβ+β+γα)x−αβγ

f(x) = {x}^{3} - 2 {x}^{2} - 7x + 14f(x)=x

3

−2x

2

−7x+14

is the required answer

Mark as brillant please