Question

If 2/7 has a terminating decimal expansion, then why is its denominator not in the form of 2^m + 5^n?

Answer 1

Answer:

Since the denominator is not in the form 2m×5n, 2 m × 5 n , and it also contains 7 and 13 as its factors, its decimal expansion will be non-terminating repeating. The denominator is of the form 2m×5n. 2 m × 5 n . Hence, the decimal expansion of 151600 is terminating.

Step-by-step explanation:

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