If 2/7 of a number exceeds its 1/6 by 5, find the number.
Answers
Answered by
0
Exact Form:
35
2
Decimal Form:
17.5
Mixed Number Form:
17
1
2
Answered by
1
Answer:
Required number=x = 140x=140
Explanation:
Let the number be x
\frac{3}{5} \:of \:a \:number = \frac{3x}{5}
5
3
ofanumber=
5
3x
\frac{2}{7} \:of \:a \:number = \frac{2x}{7}
7
2
ofanumber=
7
2x
According to the problem given,
"3/5 of a number exceeds its 2/7 by 44"
\frac{3x}{5}-\frac{2x}{7}=44
5
3x
−
7
2x
=44
\implies \frac{21x-10x}{35}=44⟹
35
21x−10x
=44
\implies \frac{11x}{35}=44⟹
35
11x
=44
\implies x = 44 \times \frac{35}{11}⟹x=44×
11
35
\implies x = 4 \times 35⟹x=4×35
\implies x = 140⟹x=140
Therefore,
x = 140x=140
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