Physics, asked by sanu8429, 9 months ago

If Ā= 2ỉ + 7j+3k and B = 3î+2ị+5k, find
the component of Aalong B.​

Answers

Answered by vickysinghphotograph
1

Explanation:

A=2i+7j+3k

B=3i+2j+5k

now we know that

A.B=|A||B|cosQ

hope u know

_______________

i.i=j.j=k.k=1

i.j=j.k=k.i=0

___________________

use this

A.B=(2i+7j+3k)(3i^+2j^+5k)

we get

A.B=6+14+15=35

we know component/ project A on B=A.B/||B||

now we need to find out magnitude of B

It is

|B|=(3^2+2^2+5^2)^1/2

=(9+4+25)^1/2

(38)^1/2

put in component formula =35/(38)^1/2

hope it help

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