If 2÷9 =(3÷2)^-2 ÷(6÷9)^0 then find the value (2÷9)^-3
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you assume 7=1 then automatically 8=2 ,9= 3 ,10=4, 11=5 also 6=0, 5=-1 ,4=-2. now putting these values we can solve above equatio
This series has a pattern in which the digits are added first, then 2 is subtracted from
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