if 2/9 og a property costs ₹252000. find the cost of 4/7of it
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Let the property cost be Rs`x`
Given thta 2/9 of x = 252000
(2/9)× x = 252000
2x/9 = 252000
2x = 252000×9
2x = 2268000
x = 2268000/2
∴x = 1134000
4/7 of x = 4/7 of 1134000
4/7ofx = (4/7)×1134000
= 4536000/7
= 648000
∴4/7 of the property costs Rs648000
Given thta 2/9 of x = 252000
(2/9)× x = 252000
2x/9 = 252000
2x = 252000×9
2x = 2268000
x = 2268000/2
∴x = 1134000
4/7 of x = 4/7 of 1134000
4/7ofx = (4/7)×1134000
= 4536000/7
= 648000
∴4/7 of the property costs Rs648000
yasummu:
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please see the attachment.the answer is 648000 rupees.
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