if 2(a^2+b^2)=(a+b)^2 then
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Hi ,
2 ( a² + b² ) = ( a + b ) ²
2a² + 2b² - ( a + b ) ² = 0
2a² + 2b² - a² - b² - 2ab = 0
a² + b² - 2ab = 0
( a - b )² = 0
Therefore ,
a - b = 0
Option B is correct
I hope this helps you.
:)
2 ( a² + b² ) = ( a + b ) ²
2a² + 2b² - ( a + b ) ² = 0
2a² + 2b² - a² - b² - 2ab = 0
a² + b² - 2ab = 0
( a - b )² = 0
Therefore ,
a - b = 0
Option B is correct
I hope this helps you.
:)
1122krishna1111:
excellent expalantion
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