Question

if 2(a^2 + b^2)=(a+b)^2 then prove that A=b​

Answer 1

$\huge{\mathcal{\green{\underline{Answer}}}}$

$2(a {}^{2} + b {}^{2} ) = (a + b) {}^{2} \\ 2(a {}^{2} + b {}^{2} ) = a { }^{2} + b {}^{2} + 2ab \\ 2a {}^{2} + 2b {}^{2} = a {}^{2} + b { }^{2} + 2ab \\ 2a {}^{2} - a {}^{2} + 2b {}^{2} - b {}^{2} - 2ab = 0 \\ a {}^{2} + b {}^{2} - 2ab = 0 \\ (a - b) {}^{2} = 0 \\ a - b = 0 \\ a = b$

Hence proved

Answer 2

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