If 2^a=3^b=4^c ,then find the relation between a,b&c
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Answer:
a = b × [ log3/log2 ] = 2c
Step-by-step explanation:
2^a = 4^c
=> 2^a = 2^(2c)
=> a = 2c .........(i)
Now,
2^a = 3^b
log 2^a = log 3^b
a log 2 = b log 3
a = b(log3/log2) ..........(ii)
From equation (i) and (ii),
a = b × [ log3/log2 ] = 2c
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