if 2^a=3^b=6^c, then find the value of c without using log?????????
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2^a=3^b
2=(3^b)^1/a
2=3^(b/a)
3^b=6^c
3=6^(b/c)
putting the value of 3
2^(a/b)={2*3}^(b^c)
comparing the same term
a/b=b/c
c=(b^2)/a
2=(3^b)^1/a
2=3^(b/a)
3^b=6^c
3=6^(b/c)
putting the value of 3
2^(a/b)={2*3}^(b^c)
comparing the same term
a/b=b/c
c=(b^2)/a
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