Question

If 2^a = 3^b = 6^c then prove that C = ab/a+b
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Answer 1

Answer:

C=ab/(a+b)

Step-by-step explanation:

Let 2^a=3^b=6^c=k

2=k^1/a

3=k^1/b

6=k^1/c

2×3=6

K^1/a+1/b=k^1/c

1/a+1/b=1/c

C=ab/(a+b)

Answer 2

Answer:

Let 2^a =3^b = 6^c=k

2 = k^(1/a), 3 = k^(1/b) and 6= k^(1/c)

2*3=6

k^(1/a)*k^(1/b) = k^(1/c)

k^(1/a +a/b= k^(1/c)

1/a +a/b = 1/c

a+b/ab = 1/c

c= ab/a+b Hence, Proved