Question

if 2^a = 3^b = 6^c then show that c = ab/a+b

Answer 1

 2^a = 3^b = 6^c so 2 = 6^(c/a ) and 3 = 6^(c/b) multiply both to get 6 = 6^( c/ a+ c/b) or 1 = c/a + c/b or 1 = c(1/a + 1/b) = c(a +b)/(ab) or c = ab/(a+b 

Answer 2

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