Question

if[2-a+b,b]=[6,2] then what will be the value of a

Answer 1

[2-a+b,b]=[6,2]
i.e.,  
2-a+b = 6, b=2
substitute b=2 in 2-a+b=6
2-a+2 = 6
4-a = 6
a = 4-6
a = -2

Answer 2

[2-a+b,b]=[6,2]
Combine all similar variables in the expression.[2-a+b^(2)]=[6,2]
Reorder the polynomial 2-a+b^(2) alphabetically from left to right, starting with the highest order term.[b^(2)-a+2]=[6,2]
Remove the parentheses around the expression b^(2)-a+2.b^(2)-a+2=[6,2]
Remove the parentheses around the expression 6,2.b^(2)-a+2=6,2
Move all terms not containing a to the right-hand side of the equation.-a=-b^(2)-2+6,2
Add 6,2 to -2 to get 60.-a=-b^(2)+60
Multiply each term in the equation by -1.-a*-1=-b^(2)*-1+60*-1
Multiply -a by -1 to get a.a=-b^(2)*-1+60*-1
Simplify the right-hand side of the equation by multiplying out all the terms.a=b^(2)-60