Question

If 2 A current passes through the cross section of a wire in 5 seconds then number of electrons crossing that area of wire in 1 min. are :​

Answer 1

Answer: Given

I=2A,T=5 sec

|=Q/T

Q=10C

In one min

1 min=60 sec

I=Q{/T

Q=120C

Charge of electron =1.6×10^-19

So no of e flowing in 1 min =120/1.6×10^-19

=7.5×10^20

There no of electron flowing in one min =7.5×10^20