Question

if 2(a square + b square ) =(a-b) whole square then show that a+b=0
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Answer 1

Answer:

Refer the detailed solution

Step-by-step explanation:

Given   $2(a^2+b^2)=(a-b)^2$

         $\Rightarrow 2a^2+2b^2=a^2+b^2-2ab$, using identity $(x-y)^2=x^2+y^2-2xy$

        $\Rightarrow 2a^2+2b^2-a^2-b^2+2ab=0$, transpose all the terms to LHS

        $\Rightarrow a^2+b^2+2ab=0\\\Rightarrow (a+b)^2=0\\\therefore a+b=0$, since $x^2+y^2+2xy=(x+y)^2$

Answer 2

answer and explanation in the picture