if 2(a²+b²)=(a-b)² then show that a+b=0
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Answer:
2(a^2+b^2)=(a-b)^2
2(a^2+b^2)=a^2+b^2-2ab
-2ab=2(a^2+b^2)-(a^2+b^2)
-2ab=a^2+b^2
a^2+b^2+2ab=0
(a+b)^2=0
a+b=root0
a+b=0
hence proved
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