if 2(a²+b²)=(a+b)² then show that a=b
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Answered by
56
2(a^2 + b^2 ) = (a + b)^2
2a^2 + 2b^2 = a^2 + b^2+ 2ab
a^2 + b^2 = 2ab
a^2 - 2ab + b^2 = 0
(a-b)^2 = 0
a-b = 0
a= b
2a^2 + 2b^2 = a^2 + b^2+ 2ab
a^2 + b^2 = 2ab
a^2 - 2ab + b^2 = 0
(a-b)^2 = 0
a-b = 0
a= b
shubhashish34:
thnx for ur help
Answered by
44
Given, 2(a²+b²) = (a+b)²
⇒ 2a²+2b²-(a+b)²=0
⇒ 2a²+2b²-(a²+b²+2ab)=0
⇒ 2a²+2b²-a²-b²-2ab=0
⇒ a²+b²-2ab=0
⇒ (a-b)²=0
⇒ a-b=0
∴ a=b
Hence, it is proved.
⇒ 2a²+2b²-(a+b)²=0
⇒ 2a²+2b²-(a²+b²+2ab)=0
⇒ 2a²+2b²-a²-b²-2ab=0
⇒ a²+b²-2ab=0
⇒ (a-b)²=0
⇒ a-b=0
∴ a=b
Hence, it is proved.
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