Question

if -2&3 are the zeroes of the quadratic polynomials x²+(p+1)x+q find the value of p and q​

Answer 1

Answer:

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Answer 2

Given : -2 and 3 are zeroes of equation x² +(p+1)x + q.

To find : Value of p and q

Solution :

If -2 is a zero of the given equation, x when substituted to be equal to -2 will make the whole equation equal to 0.

=> x² + (p+1)x + q = 0

=> (-2)² + (p+1)(-2) + q = 0

=> 4 -2p -2 + q = 0

=> 2 - 2p + q = 0 ----(1.)

For x = 3 :

=> x² + (p + 1)x + q = 0

=> (3)² + (p + 1)(3) + q = 0

=> 9 + 3p + 3 + q = 0

=> 12 + 3p + q = 0 ----(2.)

Equation (1) - Equation (2)

=> 2 - 2p + q - 12 - 3p - q = 0

=> -10 - 5p = 0

=> -10 = 5p

=> -10/5 = p

=> -2 = p

Put this value of p in equation (1)

=> 2 - 2 (-2) +q = 0

=> 2 + 4 + q = 0

=> q = -2 -4

=> q = -6

So the required value of p and q are -2 and -6.