if 2 and 1/2 are the zeros of polynomial 4x^2 -2x -(k-4)
Answers
Answered by
0
Answer:
hey mate.. your answer:
Firstly, they have given that 2 and 1/2 are the zeroes.
So, basically, you should substitute these values one by one in the equation for x
in the first case,
p(x) = 4x²-2x-(k-4)
p(x) = 4x²-2x-k + 4
p(x) = 4 (2) ² - 2(2) -k+4=0
64-4-k+4=0
64-k=0
k=64
do the same taking 1/2..
hope this helps
please mark me as the Brainliest
Answered by
0
Step-by-step explanation:
p(x)=4x^2-2x-(k-4)
p(x)=4×2^2-2×2-(1/2-4)
p(x)=16-4-7/2
p(x)=12-7/2
p(x)=17/2
Similar questions