if 2 and -1/4 are the zeroes of the polynomial 3x³-2x²-7x-2.find the third zero of the polynomial
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Answer:
third zero is -13/12
Step-by-step explanation:
SOLUTION :
We have p(x) = 3x³ - 2x² - 7x - 2 where a=3, b=(-2), c=(-7), d=(-2)
and α = 2 and β = -1/4
We need to find γ(third zero)
So, SUM OF ZEROES OF A CUBIC POLYNOMIAL:
α + β + γ = -b/a
2 + (-1/4) + γ = -(-2)
(-1/4) + γ = (2/3) - 2
γ = (-4/3) + 1/4
therefore, γ = (-13/12)
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