If 2 and _3 are are zeroes of rhe polynomial x2 +(a+1)x+b tjen find a and b
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f(x) = x^2 + (a +1)x + b
f(2) = 2x2 + (a + 1)2 + b =0
= 4 + 2a+2 +b =0
= 2a + b + 6 =0
f(-3) = (-3)^2 + (a +1)(-3) +b =0
=> 9 - 3a -3 + b =0
=>3a - b -6 =0
by solving we get , a= 0 and b = -6
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