If 2 and -3 are the roots of qiadratic equation then find the equati
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Answered by
1
Answer:
let the. two roots be p,q.
if the roots are p,q then quadratic equation is
x^2-(p+q)x+(pq)....
p=2,q=3...
p+q=2-3=-1..
pq=2(-3)=-6....
there fore the quadratic equation is....
x^2-(-1)X+(-6)
x^2+x-6....
hope it help you follow mee and mark me as BRAINLIEST...
Answered by
0
Let the quadratic equation be
ax^2 + bx + c
The zeroes of the quadratic polynomial are
2 and -3
Let,
m = 2
n = -3
m + n = - b/a
mn = c/a
Let,
a = 1
then,
m + n = - b/a
2 + -3 = - b/1
- 1 = - b
b = 1
and
mn = c/a
- 3 × 2 = c/1
- 6 = c
c = - 6
Therefore the quadratic equation is
x^2 + x - 6
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