if 2 and 3 are the roots of x^2 + px + q = 0 ,
find the value of p and q
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Answered by
1
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p(x) = x² + px + q = 0
Sum of zeroes = -b/a
2+3=-b/1
5=-(p)
p=-5
product of zeroes = c/a
2×3=c/1
6=c
c=6
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...Hope it helps....
Answered by
1
Answer:
p = -5 & q = 6
Step-by-step explanation:
We know that :
alpha + beta = -b/a
2+3 = -p
p = -5
alpha × beta = c/a
2×3 = q
q = 6
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