Question

if 2 and -3 are the zereos of the quadratic polynomial x^2+(a+1)x+b;then find the values of a and b​ pls answer quick

Answer 1

Answer:

a = - 2

b = - 6

Step-by-step explanation:

${x}^{2} + (a + 1)x + b = 0 \\ \alpha = 2 \: \: \: \: \: \beta = - 3 \\ \alpha + \beta = 2 + ( - 3) = 2 - 3 = - 1 \\ \alpha \beta = 2 \times - 3 = - 6 \\ {x}^{2} - 1x - 6 = 0 \\ a + 1 = - 1 \\ a = - 1 - 1 = - 2 \\ b = - 6$