If 2 and 3 are the zeroes of a polynomial 3x4-12x2+8 then find all the other zeroes
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2 and 3 are zero of given polynomial so (x-2) and (x-3) are factors of given polynomial
Now (x-2)×(x-3) =x^2-2x-3x+6=x^2-5x+6
Now
(3x^4+12x^2+8)÷(x^2-5x+6)
We get quotient
And reminder will be the zero
Now factor of get quotient and equal to zero
You will get yr ans
sangharsh1234:
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