If 2 and -3 are the zeroes of polynomial x^2+(a+1)x+b then find the value of a and b .
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Step-by-step explanation:
Sum of roots =-b/a
So 2+(-3)=-(a+1)
a=1-1=0
And product of roots =c/a
Therefore 2*(-3)=-6
In equation x²+(a+1)x+b
Here b=product of roots=-6
And a=sum of roots=0
a=0and c =-6
Thank you
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