Question

if-2 and 3 are the zeroes of the polynomial p(x) 2x^3-x^2+ax+b then find the values of a and b​

Answer 1

Answer:

a=-13, b=-6

Step-by-step explanation:

If a number is the zero of the polynomial then if we substitute the value then the answer will be zero..

Hence,

2(-2)^3-(-2)^2+a(-2)+b=0

b-2a=20-------(1)

And

2(3)^3-(3)^2+a(3)+b=0

So b+3a=-45----------(2)

Solving equations (1) and (2)..

We get a=-13 and b=-6

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