Question

If 2 and -3 are the zeroes of the quadratic polynomial x^2 + (a +1)x +b, then find the values of a and b.

Answer 1

Step-by-step explanation:

w8 ,

we know that

on comparison

ax²+bx+c

a= 1,b= (a+1),c= b

sum of zero = 2

product of zero = -3

solution:-b

i) sum of zero

alpha +beta = -b/a

2= - ( a+1) / 1

2= a-1

a= 3

ii) product of zero

alpha ×beta =c/a

-3=b/1

b = -3

we can easily find the value of a and b

a= 3, b = -3