Math, asked by princesschinmay, 1 year ago

If 2 and -3 are the zeroes of the quadratic polynomial x^2+(a+1)x+b ,then find the value of a&b.

Answers

Answered by ssjosh1967
2
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Answered by kdhineshalaguvel
1

Answer:

Step-by-step explanation:

p(x)= x^2+(a+1)x+b

zeros of polynomial are 2,-3

sum of zeros = -b/a

               2+-3 = -(a+1)/1

                  -1  = -a-1

                 -1+1 =-a

                  0 =a

product of zeros = c/a

                 2 x -3  = b/1

                       -6 =b

             A=0 ;     b=     -6

                               

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