If 2 and -3 are the zeroes of the quadratic polynomial x^2+(a+1)x+b ,then find the value of a&b.
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Step-by-step explanation:
p(x)= x^2+(a+1)x+b
zeros of polynomial are 2,-3
sum of zeros = -b/a
2+-3 = -(a+1)/1
-1 = -a-1
-1+1 =-a
0 =a
product of zeros = c/a
2 x -3 = b/1
-6 =b
A=0 ; b= -6
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