Math, asked by Praveenatan, 10 months ago

If 2 and -3 are the zeroes of the quadratic polynomial x2 + (a + 1) x + b; then find the values of a and b.

Answers

Answered by narissa050707
1

Answer:

{x}^{2} - 6x + 8 = (x - 4)(x - 2)

alpha=4 and beta=2

answer = 4-2 = 2

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Step-by-step explanation:

Answered by Anonymous
1

Given ,

alpha = 2

beta = -3

alpha + beta = -b/a

2-3=-(a+1)/1

-1=-a-1

a=-1+1

a=0

alpha . beta =c/a

2.-3=b/1

-6=b

or,b=-6

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