If 2 and -3 are the zeroes of the quadratic polynomial x2 + (a + 1) x + b; then find the values of a and b.
Answers
Answered by
1
Answer:
{x}^{2} - 6x + 8 = (x - 4)(x - 2)
alpha=4 and beta=2
answer = 4-2 = 2
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Step-by-step explanation:
Answered by
1
Given ,
alpha = 2
beta = -3
alpha + beta = -b/a
2-3=-(a+1)/1
-1=-a-1
a=-1+1
a=0
alpha . beta =c/a
2.-3=b/1
-6=b
or,b=-6
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