Question

If 2 and -3
are the zeroes of the
quadratic polynomial x2+(a+1) x+b
then find the value
, then find the value of a and b.
​

Answer 1

Answer:

${x}^{2} - x - 6$

Step-by-step explanation:

zeroes are 2 and -3

general formula for quadratic polynomial with zeroes is

${x}^{2} + (sum \: of \: zeroes)x + (product \: of \: zeroes)$

So Sum of zeroes here is 2+(-3)= -1

Product of zeroes= 2*(-3)= -6

So our polynomial will be:

${x}^{2} - x - 6$

Mark as Brainliest and Follow me