if -2 and 3 are the zeroes of
the quadratic polynomial x² + ( a+1) X+ b, then find the value
of a and b
pls give the ans fast I need it urgently
Answers
Answered by
1
Answer:
a = -10 and b = 18
Step-by-step explanation:
α = 3
β = -2
Place α and β in -
==: x² + (a+1)x + b = 0
==: (3)² + (a+1) 3 - b = 0
==: 9 + 3a + 3 - b = 0
==: 12 + 3a + b = 0
==: 3a + b = -12 ........(1)
==: x² + (a+1)x + b = 0
==: (-2)² + (a+1) (-2) + b = 0
==: 4 - 2a - 2 + b = 0
==: -2a + b = -2 .......(2)
From 1 and 2 we get,
a = -10 and b = 18
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Answered by
0
Answer:
a =-10 ß=18
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