Question

if -2 and 3 are the zeroes of
the quadratic polynomial x² + ( a+1) X+ b, then find the value
of a and b
pls give the ans fast I need it urgently ​

Answer 1

Answer:

a = -10 and b = 18

Step-by-step explanation:

α = 3

β = -2

Place α and β in -

==: x² + (a+1)x + b = 0

==: (3)² + (a+1) 3 - b = 0

==: 9 + 3a + 3 - b = 0

==: 12 + 3a + b = 0

==: 3a + b = -12  ........(1)

==: x² + (a+1)x + b = 0

==: (-2)² + (a+1) (-2) + b = 0

==: 4 - 2a - 2 + b = 0

==: -2a + b = -2    .......(2)

From 1 and 2 we get,

a = -10 and b = 18

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Answer 2

Answer:

a =-10 ß=18

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