If 2 and -3 are the zeroes of the quadratic polynomial x²+(a+1)x+b, then find the values of a and b.If 2 and -3 are the zeroes of the quadratic polynomial x²+(a+1)x+b, then find the values of a and b.
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Compare given equation with the general form of quadratic equation, which ax2+bx+c=0
a=(a−b),b=5(a+b),c=−2(a−b)
Find Discriminant:
D=b2−4ac
=(5(a+b))2−4(a−b)(−2(a−b))
=25(a+b)2+8(a−b)2
=17(a+b)2+{8(a+b)2+8(a−b)2}
=17(a+b)2+16(a2+b2)
Which is always greater than zero.
Equation has real and unequal roots.
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