Question

if 2 and -3 are the zeroes of the quadratic polynomial x2+(a+1)x+b then find the values of a and b.

Answer 1

I THINK IT IS HELPFUL TO YOU.....

Answer 2

Answer:

Step-by-step explanation:

Let us take a=2 and b=-3

We know alpa +beta@=-b/a and alpha.beta=c/a

By eq x square +a+1x+b

-b/a=-(a+1)/1=-a-1

C/a=b/1

Alpha=@ and beta=&

@+&=2+(-3)=-1

@.&=2×-3=-6

Now

-a-1=-1

a=0

b/1= -6

b=-6

Just to check it substitute the value of a and b in eq n c whether you get 2 and -3

X^2+0+1x+(-6)

X^2+1x-6

By factorisation

X^2+(3x-2x)-6

X(x+3)-2(x+3)

X=-3 and x=2

Hope you got the answer

And its helpful for u