Question

If -2 and 3 are the zeroes of the quadratic polynomial x² + (p + 1) x + q, than find the values of p and q​

Answer 1

Answer:

p=(-14), q=30

Step-by-step explanation:

If x=(-2)

x²+(p+1)x+q=0

(-2)²+(-2)(p+1)+q=0

4-2(p+1)+q=0

-2(p+1)+q=(-4)

2(p+1)+q=4--eq1

If x=3

x²+(p+1)x+q=0

(3)²+3(p+1)+q=0

9+3(p+1)+q=0

3(p+1)+q=(-9)--eq2

Add eq1 and eq2, we get

p+1=(-13)

p=(-13)-1

p=(-14)

Substitute p=(-14) in eq1

2(p+1)+q=4

2(-14+1)+q=4

2(-13)+q=4

(-26)+q=4

q=4+26

q=30

Answer 2

hope it helps uu...

the answer is p=-14

&q=30