If -2 and 3 are the zeroes of the quadratic polynomial x2 +x(a + l) + b. Find the value of 'a'and 'b'
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Hey mate☺
x2 + x(a+1)+b=0
put x=-2
-2^2 -2(a+1)+b=0
4-2a-2+b=0
2a-b=2.....(1)
x2+x(a+1)+b =0
put x=3
3^2+3(a+1)+b=0
6+3a+3+b=0
3a+b=-9......(2)
From (1) & (2)
2a+b=2
3a+b=-9
eliminate both equations,
we get
a=-11
put in 1st
2(-11)+b=2
-22+b=2
b=2+22
b=24
so, a=-11 & b=24
Hope it helps you ☺✌✌
vilasnagekar121:
Can you send me the photo of your note book solving.. I can understand it
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