Math, asked by vilasnagekar121, 1 year ago

If -2 and 3 are the zeroes of the quadratic polynomial x2 +x(a + l) + b. Find the value of 'a'and 'b'

Answers

Answered by Anonymous
1

Hey mate☺

x2 + x(a+1)+b=0

put x=-2

-2^2 -2(a+1)+b=0

4-2a-2+b=0

2a-b=2.....(1)

x2+x(a+1)+b =0

put x=3

3^2+3(a+1)+b=0

6+3a+3+b=0

3a+b=-9......(2)

From (1) & (2)

2a+b=2

3a+b=-9

eliminate both equations,

we get

a=-11

put in 1st

2(-11)+b=2

-22+b=2

b=2+22

b=24

so, a=-11 & b=24

Hope it helps you ☺✌✌


vilasnagekar121: Can you send me the photo of your note book solving.. I can understand it
Anonymous: okk wait
vilasnagekar121: It is wrong bro.
Anonymous: why
vilasnagekar121: A value is -2
vilasnagekar121: I know the answer but i dont to solve it
Anonymous: noo
vilasnagekar121: Ya i have it... -2.... Its there in my text book
Anonymous: ok then report my answer
Anonymous: 3 ka square 9 ana tha maine 6 likh diya toh saara answer wrong
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