Question

If 2 and 3 are the zeroes pf the polynomial x^2+(a+1)x+b; then find the value of a​

Answer 1

Step-by-step explanation:

Here's your answer

a=-6

Hope it helps!

Answer 2

Answer:

Step-by-step explanation:

In given eq. a = 1 , b = (a+1) , c = b

Sum of zeroes = 2+3 =5

. = -b/a = -(a+1) =5

= -(a+1) =5

= -a-1=5

= -a =5+1

= -a =6

= a = -6

To find the value of b

Product of zeroes = 2x3 = 6

= c/a = b/1

b = 6

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